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X^2-155X-1500=0
a = 1; b = -155; c = -1500;
Δ = b2-4ac
Δ = -1552-4·1·(-1500)
Δ = 30025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{30025}=\sqrt{25*1201}=\sqrt{25}*\sqrt{1201}=5\sqrt{1201}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-155)-5\sqrt{1201}}{2*1}=\frac{155-5\sqrt{1201}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-155)+5\sqrt{1201}}{2*1}=\frac{155+5\sqrt{1201}}{2} $
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